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MISCELLANEOUS EXERCISE - 3 (II) · Q176

Q.Find the value of r if 56Pr+6:54Pr+3=30800:1{}^{56}P_{r+6} : {}^{54}P_{r+3}= 30800:1

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56Pr+654Pr+3=56!/(50−r)!54!/(51−r)!=56!54!×(51−r)!(50−r)!=(56×55)×(51−r)=3080 (51−r)\dfrac{{}^{56}P_{r+6}}{{}^{54}P_{r+3}} = \dfrac{56!/(50-r)!}{54!/(51-r)!} = \dfrac{56!}{54!}\times\dfrac{(51-r)!}{(50-r)!} = (56\times55)\times(51-r) = 3080\,(51-r). Setting this equal to 30800: 3080 (51−r)=30800⇒51−r=10⇒r=413080\,(51-r)=30800 \Rightarrow 51-r=10 \Rightarrow r=41.

✓Final answer

r = 41

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