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EXERCISE 2.2 · Q43

Q.Find ∑r=110(5r−3r)\displaystyle\sum_{r=1}^{10}(5^r-3^r).

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$\sum_{r=1}^{10}(5^r-3^r)=\dfrac{5(5^{10}-1)}4-\dfrac{3(3^{10}-1)}2=\dfrac{5(9765624)}4-\dfrac{3(59048)}2=12 …

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