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EXERCISE 2.2 · Q25

Q.For the following G.P., find SnS_n: 0.7,0.07,0.007,…0.7, 0.07, 0.007, \ldots

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✓ Free question

a=0.7,r=0.1a=0.7, r=0.1; Sn=0.7(1−0.1n)1−0.1=0.70.9(1−0.1n)=79(1−0.1n)S_n=\dfrac{0.7(1-0.1^n)}{1-0.1}=\dfrac{0.7}{0.9}(1-0.1^n)=\dfrac79(1-0.1^n).

✓Final answer

Sn=79(1−0.1n)S_n=\dfrac79(1-0.1^n).

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