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EXERCISE 2.2 · Q45

Q.If one invests Rs. 10,000 in a bank at a rate of interest 8% per annum, how long does it take to double the money by compound interest? [(1.08)5=1.47(1.08)^5=1.47]

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We need (1.08)n=2(1.08)^n=2. Taking logarithms, n=log⁡2log⁡1.08≈0.30100.0334≈9.01n=\dfrac{\log2}{\log1.08}\approx\dfrac{0.3010}{0.0334}\approx9.01, so about 9 years. As a check against the given hint (1.08)5=1.47(1.08)^5=1.47: $(1.08)^9=(1.08)^5\times(1.08)^4\approx1.47\times1 …

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