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Miscellaneous Exercise 2 · Q60

Q.If cosec θ+cot⁡θ=52\text{cosec}\,\theta + \cot\theta = \dfrac{5}{2}, then the value of tan⁡θ\tan\theta is: A) 1425\dfrac{14}{25} B) 2021\dfrac{20}{21} C) 2120\dfrac{21}{20} D) 1516\dfrac{15}{16}

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Step 1. cosec θ+cot⁡θ=52\text{cosec}\,\theta+\cot\theta=\tfrac52 … (1). Since cosec2θ−cot⁡2θ=1\text{cosec}^2\theta-\cot^2\theta=1: cosec θ−cot⁡θ=25\text{cosec}\,\theta-\cot\theta=\tfrac25 … (2).

Step 2. Adding: 2 cosec θ=52+25=2910⇒cosec θ=29202\,\text{cosec}\,\theta=\tfrac52+\tfrac25=\tfrac{29}{10}\Rightarrow\text{cosec}\,\theta=\tfrac{29}{20}. …

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