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Miscellaneous Exercise 2 · Q64

Q.The value of tan⁡1°tan⁡2°tan⁡3°⋯tan⁡89°\tan 1° \tan 2° \tan 3° \cdots \tan 89° is equal to: A) −1 B) 1 C) π2\dfrac{\pi}{2} D) 2

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Step 1. Pair the 88 factors from 1° to 89° (excluding 45°) into 44 pairs: (tan⁡1°,tan⁡89°),(tan⁡2°,tan⁡88°),…(\tan1°,\tan89°), (\tan2°,\tan88°),\dots

Step 2. In each pair, tan⁡θ⋅tan⁡(90°−θ)=tan⁡θ⋅cot⁡θ=1\tan\theta\cdot\tan(90°-\theta)=\tan\theta\cdot\cot\theta=1, since tan⁡(90°−θ)=cot⁡θ\tan(90°-\theta)=\cot\theta. …

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