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Exercise 3.1 · Q2

Q.Find the value of cos⁡75°\cos 75°

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✓ Free question

Step 1: Write 75°=45°+30°75°=45°+30° and use cos⁡(A+B)=cos⁡Acos⁡B−sin⁡Asin⁡B\cos(A+B)=\cos A\cos B-\sin A\sin B.

Step 2: cos⁡75°=cos⁡45°cos⁡30°−sin⁡45°sin⁡30°=12⋅32−12⋅12=3−122\cos75°=\cos45°\cos30°-\sin45°\sin30°=\dfrac{1}{\sqrt2}\cdot\dfrac{\sqrt3}{2}-\dfrac{1}{\sqrt2}\cdot\dfrac{1}{2}=\dfrac{\sqrt3-1}{2\sqrt2}.

Step 3: Rationalise to get 6−24\dfrac{\sqrt6-\sqrt2}{4}; note this equals sin⁡15°\sin15° since 75°+15°=90°75°+15°=90°.

✓Final answer

cos⁡75°=6−24\cos75°=\dfrac{\sqrt6-\sqrt2}{4}

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