Skip to content
Exercise 3.1 · Q18

Q.Prove that: cos⁡15°−sin⁡15°cos⁡15°+sin⁡15°=13\dfrac{\cos15°-\sin15°}{\cos15°+\sin15°}=\dfrac{1}{\sqrt3}

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
15% · 18/119 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1: Divide numerator and denominator of cos⁡15°−sin⁡15°cos⁡15°+sin⁡15°\dfrac{\cos15°-\sin15°}{\cos15°+\sin15°} by cos⁡15°\cos15°: 1−tan⁡15°1+tan⁡15°\dfrac{1-\tan15°}{1+\tan15°}.

Step 2: This is tan⁡(45°−15°)=tan⁡45°−tan⁡15°1+tan⁡45°tan⁡15°=1−tan⁡15°1+tan⁡15°\tan(45°-15°)=\dfrac{\tan45°-\tan15°}{1+\tan45°\tan15°}=\dfrac{1-\tan15°}{1+\tan15°} since tan⁡45°=1\tan45°=1. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.