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Exercise 3.1 · Q16

Q.Prove that: tan⁡10°+tan⁡35°+tan⁡10°tan⁡35°=1\tan10°+\tan35°+\tan10°\tan35°=1

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Step 1: Note 10°+35°=45°10°+35°=45°, so tan⁡(10°+35°)=tan⁡45°=1\tan(10°+35°)=\tan45°=1.

Step 2: By the tangent-sum formula, tan⁡45°=tan⁡10°+tan⁡35°1−tan⁡10°tan⁡35°=1\tan45°=\dfrac{\tan10°+\tan35°}{1-\tan10°\tan35°}=1. …

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