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Exercise 3.3 · Q39

Q.Find the value of: sin⁡π8\sin\dfrac{\pi}{8}

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✓ Free question

Step 1: Write π8\dfrac{\pi}{8} as half of π4\dfrac{\pi}{4}, and use 1−cos⁡θ=2sin⁡2θ21-\cos\theta=2\sin^2\dfrac{\theta}{2} with θ=π4\theta=\dfrac{\pi}{4}.

Step 2: sin⁡2π8=1−cos⁡π42=1−222=2−24\sin^2\dfrac{\pi}{8}=\dfrac{1-\cos\frac{\pi}{4}}{2}=\dfrac{1-\frac{\sqrt2}{2}}{2}=\dfrac{2-\sqrt2}{4}.

Step 3: Since π8\dfrac{\pi}{8} is in the first quadrant, sin⁡π8>0\sin\dfrac{\pi}{8}>0: sin⁡π8=2−22\sin\dfrac{\pi}{8}=\dfrac{\sqrt{2-\sqrt2}}{2}.

✓Final answer

sin⁡π8=2−22\sin\dfrac{\pi}{8}=\dfrac{\sqrt{2-\sqrt2}}{2}

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