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Exercise 3.3 · Q40

Q.Find the value of: cos⁡π8\cos\dfrac{\pi}{8}

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✓ Free question

Step 1: Use 1+cos⁡θ=2cos⁡2θ21+\cos\theta=2\cos^2\dfrac{\theta}{2} with θ=π4\theta=\dfrac{\pi}{4}.

Step 2: cos⁡2π8=1+cos⁡π42=1+222=2+24\cos^2\dfrac{\pi}{8}=\dfrac{1+\cos\frac{\pi}{4}}{2}=\dfrac{1+\frac{\sqrt2}{2}}{2}=\dfrac{2+\sqrt2}{4}.

Step 3: Take the positive root (first quadrant): cos⁡π8=2+22\cos\dfrac{\pi}{8}=\dfrac{\sqrt{2+\sqrt2}}{2}.

✓Final answer

cos⁡π8=2+22\cos\dfrac{\pi}{8}=\dfrac{\sqrt{2+\sqrt2}}{2}

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