Skip to content
Exercise 3.3 · Q54

Q.Prove the following: cos⁡7°cos⁡14°cos⁡28°cos⁡56°=sin⁡68°16cos⁡83°\cos7°\cos14°\cos28°\cos56°=\dfrac{\sin68°}{16\cos83°}

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
45% · 54/119 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1: With A=7°A=7°: cos⁡7°cos⁡14°cos⁡28°cos⁡56°=sin⁡(16×7°)16sin⁡7°=sin⁡112°16sin⁡7°\cos7°\cos14°\cos28°\cos56°=\dfrac{\sin(16\times7°)}{16\sin7°}=\dfrac{\sin112°}{16\sin7°}.

Step 2: sin⁡112°=sin⁡(180°−112°)=sin⁡68°\sin112°=\sin(180°-112°)=\sin68°, and sin⁡7°=cos⁡(90°−7°)=cos⁡83°\sin7°=\cos(90°-7°)=\cos83°. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.