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Numerical · Q18

Q.A car travels at a speed of 50 km/hr for 30 minutes, at 30 km/hr for the next 15 minutes and then at 70 km/hr for the next 45 minutes. What is the average speed of the car?

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Leg 1: 50 km/hr for 30 min (0.5 h) → distance =50×0.5=25=50\times0.5=25 km. Leg 2: 30 km/hr for 15 min (0.25 h) → distance =30×0.25=7.5=30\times0.25=7.5 km. Leg 3: 70 km/hr for 45 min (0.75 h) → distance =70×0.75=52.5=70\times0.75=52.5 km. Total distance =25+7.5+52.5=85=25+7.5+52.5=85 km. Total time =0.5+0.25+0.75=1.5=0.5+0.25+0.75=1.5 h. Average speed =851.5≈56.67=\dfrac{85}{1.5}\approx 56.67 km/hr. [!ANSWER] ≈ 56.67 km/hr

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