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Answer in brief · Q9

Q.ix. How much heat is evolved when 12 g of CO reacts with NO2_2 ? The reaction is : 4 CO(g)+2 NO2(g)→4 CO2(g)+N2(g)\mathrm{4\,CO(g) + 2\,NO_2(g) \rightarrow 4\,CO_2(g) + N_2(g)}, ΔrH0\Delta_r H^0 = -1200 kJ

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Step 1. Molar mass of CO = 12 + 16 = 28 g/mol; moles of CO = 12 g / 28 g mol-1 = 0.4286 mol.

Step 2. The given equation, 4CO(g) + 2NO2(g) → 4CO2(g) + N2(g), ΔrH0 = -1200 kJ, is written for 4 moles of CO reacting, releasing 1200 kJ.

Step 3. Heat released per mole of CO = 1200 kJ / 4 mol = 300 kJ/mol. …

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