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Answer the following questions · Q4

Q.iv. Although ΔS\Delta S for the formation of two moles of water from H2\mathrm{H_2} and O2\mathrm{O_2} is -327JK−1^{-1}, it is spontaneous. Explain. (Given ΔH\Delta H for the reaction is -572 kJ).

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Step 1. Spontaneity is decided by TOTAL entropy (system+surroundings), not the system's entropy alone.

Step 2. The system's entropy here is given: ΔSsys = -327 J K-1 (three moles of gas becoming two moles of liquid, a large ordering).

Step 3. The surroundings' entropy change: ΔSsurr = -ΔH/T = -(-572000 J)/298 K = +1919 J K-1 (the large heat released, 572 kJ, is absorbed by the surroundings, raising their entropy).

Step 4. ΔStotal = ΔSsys + ΔSsurr = -327 + 1919 = +1592 J K-1, which is strongly positive. …

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