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Q.Take two test tubes and label them as A and B. Add Zinc filings in both the test tubes. In the test tube labelled A add 5 mL of 1M HCl and in test B 5 mL of acetic acid. Keep the test tubes on the stand. Note down your observations. a. Do you see any effervescence coming from the two test tubes ?
b. Which gas is evolved ?
c. How do you identify the gas ?
d. What is the relative rate at which the gas is evolved in the two test tubes
e. Based on your observations comment on the strength of acids used.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Step 1. Zinc reacts with a dilute acid to liberate hydrogen gas: Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g). Both HCl (tube A) and acetic acid (tube B) supply H+, so both tubes are expected to show effervescence (bubbling) as this reaction proceeds.

Step 2. (b) The gas evolved in both cases is hydrogen, H2. (c) Hydrogen is identified by holding a burning splint at the mouth of the test tube -- it burns with a characteristic squeaky 'pop' sound (distinct from, e.g., a glowing splint relighting, which would indicate oxygen).

Step 3. (d) The RATE of gas evolution differs sharply between the two tubes. HCl is a strong acid (section 3.4) -- it is almost completely dissociated, so a 1M HCl solution has [H+] very close to 1 M. Acetic acid is a weak acid -- at a comparable concentration it is only partially dissociated (a few percent, per the degree-of-dissociation calculations elsewhere in this chapter), so its actual [H+] is far lower than its nominal molar concentration. Since the rate of the zinc-acid reaction depends on [H+], not on the nominal acid concentration, tube A (HCl) evolves gas visibly faster and more vigorously than tube B (acetic acid). …

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