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Q.The probability that a bomb will hit a target is 0.8. Find the probability that out of 10 bombs dropped, exactly 4 will hit the target.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017Subjective· 2mImportance★★★★★
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Binomial with n=10n=10, p=0.8p=0.8; use P(X=r)=(nr)prqn−rP(X=r)=\binom{n}{r}p^r q^{n-r}.

Let XX = number of bombs (out of 10) that hit the target, X∼B(n=10, p=0.8)X\sim B(n=10,\,p=0.8), q=0.2q=0.2.

P(X=4)=(104)(0.8)4(0.2)6P(X=4) = \binom{10}{4}(0.8)^4(0.2)^6

(104)=210\binom{10}{4} = 210

(0.8)4=0.4096(0.8)^4 = 0.4096, (0.2)6=0.000064\quad (0.2)^6 = 0.000064

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