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Q.A fair coin is tossed 8 times. Find the probability that it shows heads a. exactly 5 times b. at least once.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2017Subjective· 3mImportance★★★★★
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X∼B(8,12)X\sim B\left(8,\tfrac12\right); use P(X=r)=(nr)prqn−rP(X=r)=\binom{n}{r}p^rq^{n-r} and complement for "at least once".

Let XX = number of heads in 88 tosses of a fair coin, X∼B(n=8, p=12, q=12)X\sim B\left(n=8,\ p=\dfrac12,\ q=\dfrac12\right).

(a) Exactly 5 heads:

P(X=5)=(85)(12)5(12)3=(85)(12)8=56256=732P(X=5) = \binom{8}{5}\left(\dfrac12\right)^5\left(\dfrac12\right)^3 = \binom85\left(\dfrac12\right)^8 = \dfrac{56}{256} = \dfrac{7}{32}

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