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Question 52 of 55

Q.If the mean and variance of a binomial distribution are 18 and 12 respectively, then nn is equal to ____.

(a) 36
(b) 54
(c) 18
(d) 27
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025MCQ· 2mImportance★★★★★
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For a binomial distribution, mean =np=np and variance =npq=npq; divide to get qq, then find nn.

Mean =np=18=np=18, Variance =npq=12=npq=12.

npqnp=q=1218=23\frac{npq}{np}=q=\frac{12}{18}=\frac{2}{3}

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