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Exercise 7.1 · Q14

Q.A coin is biased so that the head is 3 times as likely to occur as tail. If the coin is tossed twice, find the probability distribution of number of tails.

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Since head is 3 times as likely as tail, P(H)=3/4P(H)=3/4 and P(T)=1/4P(T)=1/4. Let X be the number of tails in 2 independent tosses: P(X=0)=P(HH)=(3/4)2=9/16P(X=0)=P(HH)=(3/4)^2=9/16; P(X=1)=2×(3/4)(1/4)=6/16=3/8P(X=1)=2\times(3/4)(1/4)=6/16=3/8 …

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