The probability distribution of a discrete random variable X is: | X = x | 1 | 2 | 3 | 4 | 5 | |---|---|---|---|---|---| | P(X = x) | k | 2k | 3k | 4k | 5k | Find $P(X \le 4)$.

> > [!TLDR] > Find $k$ from $\sum P(X=x)=1$, then sum the probabilities for $X=1,2,3,4$. > > | $X=x$ | 1 | 2 | 3 | 4 | 5 | > |---|---|---|---|---|---| > | $P(X=x)$ | $k$ | $2k$ | $3k$ | $4k$ | $5k$ | > > Since total probability is 1: …

The probability distribution of a discrete random – Class 12 Mathematics

Question 69 of 88

The probability distribution of a discrete random variable X is:

X = x	1	2	3	4	5
P(X = x)	k	2k	3k	4k	5k

Find $P(X \le 4)$ .

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2016Subjective· 2mImportance★★★★★

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Find $k$ from $\sum P(X=x)=1$ , then sum the probabilities for $X=1,2,3,4$ .

$X=x$	1	2	3	4	5
$P(X=x)$	$k$	$2k$	$3k$	$4k$	$5k$

Since total probability is 1: …

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Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.

CBSE 2024Set ANNUAL2 marks
$Q. If two coins are tossed simultaneously, write the probability distribution of the number of heads.$
›Reveal solutionSolution

Two-coin sample space $\{HH,HT,TH,TT\}$ ; $X=$ number of heads.

Sample space: $\{HH,HT,TH,TT\}$ , each with probability $\dfrac14$ . $X=$ number of heads $\in\{0,1,2\}$ .

$P(X=0)=P(TT)=\dfrac14$

$P(X=1)=P(HT)+P(TH)=\dfrac24=\dfrac12$

$P(X=2)=P(HH)=\dfrac14$

…

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CBSE 2016Set ANNUAL2 marks
$P(X \le 4)$
›Reveal solutionSolution

Find $k$ from $\sum P(X=x)=1$ , then sum the probabilities for $X=1,2,3,4$ .

$X=x$ 1 2 3 4 5
$P(X=x)$ $k$ $2k$ $3k$ $4k$ $5k$

Since total probability is 1: …

Start your 14-day free trial to see the full solution →

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