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Question 74 of 88

Q.Find the variance and standard deviation of the random variable X whose probability distribution is given below: xx: 0, 1, 2, 3; P(X=x)P(X=x): 18,38,38,18\dfrac{1}{8}, \dfrac{3}{8}, \dfrac{3}{8}, \dfrac{1}{8}.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2018Subjective· 4mImportance★★★★★
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Compute E(X)E(X) and E(X2)E(X^2) from the distribution table, then Var(X)=E(X2)−[E(X)]2\text{Var}(X)=E(X^2)-[E(X)]^2.

Given the distribution:

xx0123
P(X=x)P(X=x)18\frac1838\frac3838\frac3818\frac18

E(X)=∑x P(x)=0⋅18+1⋅38+2⋅38+3⋅18=0+38+68+38=128=32E(X) = \sum x\,P(x) = 0\cdot\frac18+1\cdot\frac38+2\cdot\frac38+3\cdot\frac18 = 0+\frac38+\frac68+\frac38 = \frac{12}{8}=\frac32

E(X2)=∑x2 P(x)=0⋅18+1⋅38+4⋅38+9⋅18=0+38+128+98=248=3E(X^2) = \sum x^2\,P(x) = 0\cdot\frac18+1\cdot\frac38+4\cdot\frac38+9\cdot\frac18 = 0+\frac38+\frac{12}{8}+\frac98 = \frac{24}{8}=3

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