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Worked Examples · Example 6.3

Q.Two wires of the same material and the same cross section are stretched on a sonometer in succession. Length of one wire is 60 cm and that of the other is 30 cm. An unknown load is applied to the first wire and second wire is loaded with 1.5 kg. If both the wires vibrate with the same fundamental frequencies, calculate the unknown load.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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n₁ = n₂ with same m gives T₁/l₁² = T₂/l₂²; T₁ = T₂(l₁/l₂)² = 1.5×(60/30)² = 6 kg-wt.

Both wires are of the same material and cross-section, so their mass per unit length m is the same. Equal fundamental frequencies with n = (1/2l)√(T/m) require

12l1T1m=12l2T2m⇒T1l12=T2l22\frac{1}{2l_1}\sqrt{\frac{T_1}{m}} = \frac{1}{2l_2}\sqrt{\frac{T_2}{m}} \Rightarrow \frac{T_1}{l_1^2} = \frac{T_2}{l_2^2} …

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