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Questions 3-24 · Q23

Q.A sonometer wire of length 0.5 m is stretched by a weight of 5 kg. The fundamental frequency of vibration is 100 Hz. Calculate linear density of wire.

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Given l=0.5l=0.5 m, weight =5=5 kg (so tension T=5×9.8=49T=5\times9.8=49 N, using g=9.8g=9.8 m/s^2), fundamental frequency n=100n=100 Hz. From n=12lT/mn=\dfrac{1}{2l}\sqrt{T/m}, squaring both sides gives n2=14l2⋅Tmn^2=\dfrac{1}{4l^2}\cdot\dfrac{T}{m}, so $m=\dfrac{T}{4l^2n^2}=\dfrac{49}{4\times(0.5)^2\times( …

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