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Worked Examples · Example 6.1

Q.Two sound waves having wavelengths 81 cm and 82.5 cm produce 8 beats per second. Calculate the speed of sound in air.

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✓ Free question

v(1/0.81 − 1/0.825) = 8 → v = 356.4 m/s.

The two waves have the same speed v but different wavelengths, so their frequencies differ: n₁ = v/λ₁, n₂ = v/λ₂ with λ₁ < λ₂ (so n₁ > n₂). The beat frequency is

n1−n2=v(1λ1−1λ2)=8n_1 - n_2 = v\left(\frac{1}{\lambda_1} - \frac{1}{\lambda_2}\right) = 8

v(10.81−10.825)=8⇒v=356.4 m/sv\left(\frac{1}{0.81} - \frac{1}{0.825}\right) = 8 \Rightarrow v = 356.4\ \mathrm{m/s}

✓Final answer

v = 356.4 m/s.

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