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Exercises · 5.1

Q.What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?

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✓ Free question

Step 1 – Identify the process

Temperature is fixed at 30°C throughout, so Boyle's law applies:

p1V1=p2V2p_1V_1 = p_2V_2

Step 2 – Data

p1=1 bar,V1=500 dm3,V2=200 dm3p_1 = 1\ \text{bar}, \quad V_1 = 500\ \text{dm}^3, \quad V_2 = 200\ \text{dm}^3

Step 3 – Solve

p2=p1V1V2=(1 bar)(500 dm3)200 dm3=2.5 barp_2 = \frac{p_1V_1}{V_2} = \frac{(1\ \text{bar})(500\ \text{dm}^3)}{200\ \text{dm}^3} = 2.5\ \text{bar}

✓Final answer

p2=2.5 bar\boxed{p_2 = 2.5\ \text{bar}} — this is the minimum pressure needed to compress the air into the smaller volume.

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