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Exercises · 11.20

Q.What happens when

(a) Borax is heated strongly,
(b) Boric acid is added to water,
(c) Aluminium is treated with dilute NaOH,
(d) BF3 is reacted with ammonia?
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Four short reaction-based questions on boron and aluminium chemistry — borax's thermal decomposition, boric acid's Lewis acidity, aluminium's amphoteric dissolution, and BF3_3's Lewis-acid–base adduct with ammonia.

  1. (a) Borax heated strongly. Borax first loses its water of crystallisation on heating, swelling up ("puffs up"/intumescence) into a fluffy, porous mass of anhydrous borax. Further strong heating melts it, and on continued heating it decomposes into a transparent glassy bead — a mixture of sodium metaborate and boric oxide (this is the basis of the borax-bead test):

Na2B4O7⋅10H2O→ΔNa2B4O7→red heat2NaBO2+B2O3\text{Na}_2\text{B}_4\text{O}_7\cdot 10\text{H}_2\text{O} \xrightarrow{\Delta} \text{Na}_2\text{B}_4\text{O}_7 \xrightarrow{\text{red heat}} 2\text{NaBO}_2 + \text{B}_2\text{O}_3

  1. (b) Boric acid added to water. Boric acid is a weak, monobasic acid, but it does not ionise by donating a proton itself. Instead it behaves as a Lewis acid: it accepts a hydroxide ion from a water molecule, releasing a proton in the process:

B(OH)3+2H2O→[B(OH)4]−+H3O+\text{B(OH)}_3 + 2\text{H}_2\text{O} \rightarrow [\text{B(OH)}_4]^- + \text{H}_3\text{O}^+

  1. (c) Aluminium treated with dilute NaOH. Aluminium is amphoteric and dissolves in alkali (as well as in acid), liberating hydrogen gas and forming soluble sodium aluminate: 2Al+2NaOH+2H2O→2NaAlO2+3H2↑2\text{Al} + 2\text{NaOH} + 2\text{H}_2\text{O} \rightarrow 2\text{NaAlO}_2 + 3\text{H}_2\uparrow …

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