Q.For which of the following media with respect to air the value of critical angle is maximum?
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Critical Angle Comparison: From Intuition to Precision
Imagine you're standing at the edge of a swimming pool, looking down at a coin at the bottom. The coin appears closer to the surface than it actually is. That's refraction — light bends when it moves from water into air. Now imagine tilting your head so you're looking at the coin from a very shallow angle. At some point, the coin suddenly vanishes. You can't see it anymore, no matter how hard you try. That vanishing point is the critical angle.
The Intuition
Light travels at different speeds in different materials. When it crosses from a denser medium (like water or glass) into a rarer medium (like air), it bends away from the normal (the imaginary line perpendicular to the surface). The larger the angle of incidence (the angle at which light hits the boundary), the more it bends away.
At a certain angle of incidence, the refracted ray bends so much that it runs exactly along the surface — it makes a 90° angle with the normal. That's the critical angle. If you increase the angle of incidence even slightly beyond this, the light can't escape at all. It reflects back into the denser medium, a phenomenon called total internal reflection.
Critical angle only exists when light travels from a denser medium to a rarer medium. Going the other way (rarer to denser), light always bends toward the normal — no critical angle, no total internal reflection.
The Precise Statement
The critical angle (θc) is the angle of incidence in the denser medium for which the angle of refraction in the rarer medium is exactly 90°.
Mathematically, from Snell's law:
n1sinθ1=n2sinθ2
Let medium 1 be the denser medium (refractive index n1) and medium 2 be the rarer medium (refractive index n2, with n2<n1). At the critical angle, θ1=θc and θ2=90∘, so sinθ2=1. This gives:
n1sinθc=n2×1
sinθc=n1n2
Where:
- θc = critical angle
- n1 = refractive index of the denser medium
- n2 = refractive index of the rarer medium
What This Tells You
The critical angle depends only on the ratio of the two refractive indices. A larger difference between n1 and n2 means a smaller critical angle — light is more "trapped" inside the denser medium. For example:
| Medium pair | n1 (denser) | n2 (rarer) | θc |
|---|---|---|---|
| Water → Air | 1.33 | 1.00 | ≈48.8∘ |
| Glass → Air | 1.50 | 1.00 | ≈41.8∘ |
| Diamond → Air | 2.42 | 1.00 | ≈24.4∘ |
The critical angle of a medium is set by its refractive index relative to air, so comparing the refractive indices of the given media directly determi …
Critical angle C=sin−1(1/n) is largest for the medium with the smallest refractive index.
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- CBSE 2026Set ANNUAL1 markMCQQ.For which of the following media with respect to air the value of critical angle is maximum?(a) crown glass(b) flint glass(c) diamond(d) water
›Reveal solutionSolution
Critical angle C=sin−1(1/n) is largest for the medium with the smallest refractive index.
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- CBSE 2022Set ANNUAL1 markQ.The ............ angle for a ray incident from a denser to rarer medium, is that angle for which the angle of refraction is 90∘.
›Reveal solutionSolution
The angle described is the critical angle.
When light travels from a denser to a rarer medium, it bends away from the normal. As the angle of incidence increases, the angle of refraction reaches 90∘ at a particular incidence angle — the critical angle θc, given by …
- CBSE 2018Set ANNUAL1 markMCQQ.Critical angle for light moving from medium I to medium II is θ. The speed of light in medium I is v. Then speed in medium II is -(a) v (1 − cos θ)(b) v/sinθ(c) v/cos θ(d) v (1 − sin θ)
›Reveal solutionSolution
Critical-angle condition sinθ=n2/n1=v1/v2 gives v2=v/sinθ.
At the critical angle θ (light going from denser medium I to rarer medium II), the refracted ray grazes at 90°:
n1sinθ=n2sin90∘⇒sinθ=n1n2.
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