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Q.Find the co-ordinates of the point which divides the line segment joining the points (5,4,2)(5, 4, 2) and (−1,−2,4)(-1, -2, 4) internally in the ratio 3:43 : 4.

Meghalaya MboseMBOSE Meghalaya 11th Board 2020Subjective· 2mImportance★★★★★
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The point dividing the segment in ratio 3:43:4 is (177,107,207)\left(\dfrac{17}{7},\dfrac{10}{7},\dfrac{20}{7}\right).

For points (5,4,2)(5,4,2) and (−1,−2,4)(-1,-2,4) divided internally in ratio m:n=3:4m:n=3:4, the section formula gives:

x=mx2+nx1m+n=3(−1)+4(5)7=−3+207=177x=\dfrac{m x_2+n x_1}{m+n} = \dfrac{3(-1)+4(5)}{7} = \dfrac{-3+20}{7}=\dfrac{17}{7}

y=my2+ny1m+n=3(−2)+4(4)7=−6+167=107y=\dfrac{m y_2+n y_1}{m+n} = \dfrac{3(-2)+4(4)}{7} = \dfrac{-6+16}{7}=\dfrac{10}{7} …

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