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Q.Find the co-ordinates of the points which trisect the line segment joining the points P(4,2,−6)P(4,2,-6) and Q(10,−16,6)Q(10,-16,6). OR If the origin is the centroid of the triangle PQR with vertices P(2a,2,6)P(2a, 2, 6), Q(−4,3b,−10)Q(-4,3b,-10) and R(8,14,2c)R(8, 14, 2c), then find the values of aa, bb and cc.

Meghalaya MboseMBOSE Meghalaya 11th Board 2023Subjective· 4mImportance★★★★★
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The trisection points are (6,−4,−2)(6,-4,-2) and (8,−10,2)(8,-10,2).

For P(4,2,−6)P(4,2,-6) and Q(10,−16,6)Q(10,-16,6), the two trisection points divide PQPQ in ratios 1:21:2 and 2:12:1.

First point R1R_1 (ratio 1:21:2 from PP):

R1=(1(10)+2(4)3, 1(−16)+2(2)3, 1(6)+2(−6)3)=(183,−123,−63)=(6,−4,−2).R_1 = \left(\dfrac{1(10)+2(4)}{3},\ \dfrac{1(-16)+2(2)}{3},\ \dfrac{1(6)+2(-6)}{3}\right) = \left(\dfrac{18}3,\dfrac{-12}3,\dfrac{-6}3\right)=(6,-4,-2).

Second point R2R_2 (ratio 2:12:1 from PP): …

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