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Q.Show that the points P(−2,3,5)P(-2, 3, 5), Q(1,2,3)Q(1, 2, 3) and R(7,0,−1)R(7, 0, -1) are collinear.

Meghalaya MboseMBOSE Meghalaya 11th Board 2022Subjective· 2mImportance★★★★★
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Since QR⃗\vec{QR} is a scalar multiple of PQ⃗\vec{PQ}, the three points are collinear.

For P(−2,3,5)P(-2,3,5), Q(1,2,3)Q(1,2,3), R(7,0,−1)R(7,0,-1):

PQ⃗=Q−P=(1−(−2), 2−3, 3−5)=(3,−1,−2)\vec{PQ} = Q-P = (1-(-2),\,2-3,\,3-5) = (3,-1,-2)

QR⃗=R−Q=(7−1, 0−2, −1−3)=(6,−2,−4)=2(3,−1,−2)=2PQ⃗\vec{QR} = R-Q = (7-1,\,0-2,\,-1-3) = (6,-2,-4) = 2(3,-1,-2) = 2\vec{PQ}

Since QR⃗=2PQ⃗\vec{QR}=2\vec{PQ}, the vectors are parallel and share the common point QQ, so P,Q,RP,Q,R lie on the same straight line.

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