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Q.Define angle of contact. Derive an expression for the ascent of a liquid in a capillary tube. OR State and prove Pascal's law. Explain the principle of a hydraulic lift.

Nagaland NbseNagaland Board of School Education (Class XI) 2022Subjective· 5mImportance★★★★★
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Capillary rise: h=2Tcos⁡θρgrh = \dfrac{2T\cos\theta}{\rho g r}.

Angle of contact: The angle of contact θ\theta between a liquid and a solid surface is defined as the angle between the tangent drawn to the liquid surface at the point of contact with the solid, and the solid surface, measured within the liquid. It depends on the nature of the liquid and solid in contact (e.g. water-glass has an acute angle of contact, mercury-glass has an obtuse one).

Derivation of capillary rise: Consider a capillary tube of internal radius rr dipped vertically into a liquid of density ρ\rho and surface tension TT, which wets the tube (angle of contact θ\theta acute). The liquid meniscus inside the tube forms a concave curved surface, and surface tension acts along the circumference of contact, tangent to the liquid surface, at angle θ\theta to the tube wall (vertical).

The upward vertical component of the surface tension force, acting along the entire circumference 2πr2\pi r of contact, is what supports the risen liquid column:

Fvertical=Tcos⁡θ×(2πr)=2πrTcos⁡θF_{vertical} = T\cos\theta \times (2\pi r) = 2\pi r T\cos\theta

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