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NCERT Exemplar · Q32

Q.Calculate the length of the arc of a circle of radius 31.0 cm which subtends an angle of π6\dfrac{\pi}{6} at the centre.

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The arc length is found by multiplying the radius by the central angle (in radians). For r=31.0r = 31.0 cm and θ=π/6\theta = \pi/6, the result is 31.0×π/6≈16.231.0 \times \pi/6 \approx 16.2 cm.

The key idea here is that arc length is a direct proportion of the radius and the angle. When the angle is given in radians, the formula is beautifully simple: s=rθs = r\theta. This works because one radian is defined as the angle that subtends an arc equal in length to the radius. So if you have θ\theta radians, you're essentially stacking θ\theta such radius-length arcs together.

Let's walk through it step by step.

  1. Identify what's given.

    The radius r=31.0r = 31.0 cm. The central angle θ=π6\theta = \dfrac{\pi}{6} radians. Notice the angle is already in radians — that's important. If it were in degrees, we'd have to convert first.

  2. Recall the arc length formula.

    For a circle, the length ss of an arc subtended by an angle θ\theta (in radians) at the centre is:

s=rθs = r\theta

This is not a coincidence — it's the definition of the radian measure.

  1. Plug in the values.

s=31.0×π6s = 31.0 \times \frac{\pi}{6}

  1. Simplify the expression.

s=31.0π6s = \frac{31.0\pi}{6}

  1. Get a numerical value (if needed). Using π≈3.1416\pi \approx 3.1416:

s≈31.0×3.14166=97.38966≈16.2316s \approx \frac{31.0 \times 3.1416}{6} = \frac{97.3896}{6} \approx 16.2316

Rounding to three significant figures (since 31.0 has three), we get s≈16.2s \approx 16.2 cm. …

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