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Q.Obtain the expression for the total energy of an electron according to Rutherford’s model of an atom. OR Draw and label the schematic arrangement of Geiger-Marsden experiment.

Nagaland NbseNagaland Board of School Education 2022Subjective· 2mImportance★★★★★
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Equating the electrostatic attraction to the required centripetal force gives the kinetic energy; adding the (negative) electrostatic potential energy gives a total energy of −e2/8πϵ0r-e^2/8\pi\epsilon_0 r.

Consider an electron of charge −e-e revolving in a circular orbit of radius rr around a nucleus of charge +e+e (as in Rutherford's planetary model). The electrostatic (Coulomb) force of attraction provides the centripetal force needed for circular motion:

mv2r=14πϵ0e2r2\frac{mv^2}{r} = \frac{1}{4\pi\epsilon_0}\frac{e^2}{r^2}

Kinetic energy:

KE=12mv2=e28πϵ0rKE = \frac{1}{2}mv^2 = \frac{e^2}{8\pi\epsilon_0 r}

Potential energy (taking zero at infinite separation):

PE=14πϵ0(e)(−e)r=−e24πϵ0rPE = \frac{1}{4\pi\epsilon_0}\frac{(e)(-e)}{r} = -\frac{e^2}{4\pi\epsilon_0 r}

Total energy: …

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