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Q.Calculate the radius of dynamically stable orbit in hydrogen atom and total energy of their electron in the orbit by Rutherford nuclear model of the atom.

Rajasthan RbseRajasthan Board Senior Secondary Examination 2025Subjective· 2mImportance★★★★★
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Bohr combined Rutherford's nuclear (planetary) picture of the atom with a quantisation rule for angular momentum, which fixes the orbit radii and energies to specific discrete values.

Note: a purely classical Rutherford (planetary) model, with an electron freely orbiting the nucleus, is unstable — an accelerating charge should radiate energy continuously and spiral into the nucleus. Bohr fixed this by adding a quantisation postulate on top of Rutherford's nuclear model, and it is this combined Bohr model that gives stable orbits, as derived below.

Radius of the orbit: For an electron of mass mm, charge −e-e, moving in a circular orbit of radius rr around a nucleus of charge +e+e (hydrogen) with speed vv, the Coulomb force provides the centripetal force:

mv2r=14πε0e2r2\dfrac{mv^2}{r} = \dfrac{1}{4\pi\varepsilon_0}\dfrac{e^2}{r^2} ... (i)

Bohr's quantisation postulate: mvr=nh2πmvr = \dfrac{nh}{2\pi} ... (ii)

From (ii): v=nh2πmrv = \dfrac{nh}{2\pi m r}. Substituting into (i) and solving for rr:

rn=ε0n2h2πme2r_n = \dfrac{\varepsilon_0 n^2 h^2}{\pi m e^2}

For n=1n=1 (hydrogen ground state), this gives the Bohr radius r1=0.529×10−10r_1 = 0.529\times10^{-10} m = 0.529 Å; in general rn=n2×0.529r_n = n^2 \times 0.529 Å.

Total energy: Total energy = kinetic + potential energy.

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