Q.An astronaut accidentally gets separated out of his small spaceship accelerating in interstellar space at a constant rate of . What is the acceleration of the astronaut the instant after he is outside the spaceship? (Assume that there are no nearby stars to exert gravitational force on him.)
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Start your 14-day free trial to unlock the full solution →In the absence of external forces (no gravity, no contact), Newton's First Law dictates that the astronaut moves with constant velocity; his acceleration is zero.
Why the astronaut's acceleration becomes zero
The spaceship accelerates at because its engines exert a thrust force. The moment the astronaut separates, he loses contact with the ship—no floor pushes on his feet, no wall presses against his back. In deep interstellar space with no nearby stars, there is no gravitational force either.
Newton's First Law tells us that an object continues in its state of motion (constant velocity) unless acted upon by a net external force. The instant the astronaut is outside, no force acts on him. Whatever velocity he had at the moment of separation—matching the ship's velocity at that instant—he retains. But velocity staying constant means acceleration is zero.
The spaceship, meanwhile, continues to accelerate away from him because its engines keep firing.
Step-by-step reasoning
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Identify forces on the astronaut before separation.
While inside, the spaceship's floor exerts a normal force on the astronaut, accelerating him along with the ship at . This normal force is the only force (ignoring negligible distant stellar gravity).
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What happens at the instant of separation?
The contact is lost. The normal force vanishes. In interstellar space far from stars, gravitational forces are negligible. The net force on the astronaut becomes
- Apply Newton's Second Law. …
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