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Q.There are 25 girls and 15 boys in class XI, and 30 boys and 20 girls in class XII. If a student from a class, selected at random, happens to be a boy, find the probability that he has been chosen from class XII.

Odisha ChseOdisha CHSE +2 Science Board Exam 2020Subjective· 4mImportance★★★★★
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Using Bayes' theorem with equally-likely class selection, P(XII∣boy)=813P(\text{XII}\mid\text{boy})=\dfrac{8}{13}.

Let E1E_1: student is from class XI, E2E_2: student is from class XII; each class is equally likely to be chosen, so P(E1)=P(E2)=12P(E_1)=P(E_2)=\dfrac12.

Class XI has 1515 boys, 2525 girls (total 4040): P(boy∣E1)=1540=38P(\text{boy}\mid E_1)=\dfrac{15}{40}=\dfrac38.

Class XII has 3030 boys, 2020 girls (total 5050): P(boy∣E2)=3050=35P(\text{boy}\mid E_2)=\dfrac{30}{50}=\dfrac35.

By the total probability rule:

P(boy)=P(E1)P(boy∣E1)+P(E2)P(boy∣E2)=12⋅38+12⋅35=316+310=15+2480=3980.P(\text{boy})=P(E_1)P(\text{boy}\mid E_1)+P(E_2)P(\text{boy}\mid E_2)=\dfrac12\cdot\dfrac38+\dfrac12\cdot\dfrac35=\dfrac{3}{16}+\dfrac{3}{10}=\dfrac{15+24}{80}=\dfrac{39}{80}. …

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