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Q.Bag I contains 5 red and 5 black balls, bag II contains 4 red and 8 black balls, bag III contains 8 red and 8 black balls. One bag is chosen at random and a ball is drawn from it. If the drawn ball is black, then find the probability that it has been drawn from bag III.

Odisha ChseOdisha CHSE +2 Science Board Exam 2024Subjective· 4mImportance★★★★★
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Applying Bayes' theorem with the black-ball probabilities from each bag gives P(Bag III∣black)=310P(\text{Bag III}\mid\text{black}) = \dfrac{3}{10}.

Let B1,B2,B3B_1,B_2,B_3 be the events of choosing bag I, II, III (each with probability 13\dfrac13), and EE = drawn ball is black.

P(E∣B1)=510=12P(E\mid B_1) = \dfrac{5}{10}=\dfrac12, P(E∣B2)=812=23\quad P(E\mid B_2)=\dfrac{8}{12}=\dfrac23, P(E∣B3)=816=12\quad P(E\mid B_3)=\dfrac{8}{16}=\dfrac12

By the law of total probability: …

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