Skip to content
NCERT Exemplar · Q20

Q.A long straight horizontal wire carrying a current of 25 A25\ \text{A} rests fixed on a table. A second straight wire PQ of length 1 m1\ \text{m} and mass 2.5 g2.5\ \text{g} carries the same 25 A25\ \text{A} current but in the opposite direction; it is held horizontal and parallel to the fixed wire, directly above it, and is free to move vertically. Because the two currents are anti-parallel they repel, so PQ floats in equilibrium at a height hh above the fixed wire. Find hh.

Odisha ChseSubjective· 3mImportance★★★★★est
82% · 45/55 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Anti-parallel currents repel, so the fixed wire pushes wire PQ upward. In equilibrium this repulsive force equals the weight of PQ. Setting μ0I22πh⋅L=mg\dfrac{\mu_0 I^2}{2\pi h}\cdot L=mg and solving gives h≈5.1×10−3 m≈0.51 cmh\approx5.1\times10^{-3}\ \text{m}\approx0.51\ \text{cm}.

Concept & formula

Two long parallel wires a distance hh apart, carrying currents I1I_1 and I2I_2, exert a force per unit length on each other of

FL=μ0I1I22πh.\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi h}.

Parallel currents attract; anti-parallel currents (as here) repel. The repulsion on PQ is directed upward and can support its weight.

Step 1 — equilibrium condition

With I1=I2=I=25 AI_1=I_2=I=25\ \text{A} and length L=1 mL=1\ \text{m}, the total upward force is μ0I2L2πh\dfrac{\mu_0 I^2 L}{2\pi h}. It balances the weight mgmg of PQ:

μ0I2L2πh=mg.\frac{\mu_0 I^2 L}{2\pi h}=mg.

Step 2 — solve for hh

h=μ0I2L2πmg.h=\frac{\mu_0 I^2 L}{2\pi mg}.

Insert μ0=4π×10−7 T⋅m/A\mu_0=4\pi\times10^{-7}\ \text{T·m/A}, I=25 AI=25\ \text{A}, L=1 mL=1\ \text{m}, m=2.5×10−3 kgm=2.5\times10^{-3}\ \text{kg}, g=9.8 m/s2g=9.8\ \text{m/s}^2: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.