Skip to content
Exercises · 10.8

Q.What is the Brewster angle for air to glass transition? (Refractive index of glass = 1.51.5.)

Odisha ChseTextbookSubjective· 2mImportance★★★★★est
22% · 10/46 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Brewster's law gives tan⁡θB=μ\tan\theta_B = \mu, so for glass with μ=1.5\mu = 1.5, the Brewster angle is θB=tan⁡−1(1.5)≈56.3∘\theta_B = \tan^{-1}(1.5) \approx 56.3^\circ.

Step 1: Brewster's law

When unpolarised light is incident on a transparent medium at the Brewster angle θB\theta_B, the reflected ray is completely (linearly) polarised, and the reflected and refracted rays are mutually perpendicular. This condition gives:

tan⁡θB=μ\tan\theta_B = \mu

where μ\mu is the refractive index of the second medium (glass) relative to the first (air).

Step 2: Substitute the given value

tan⁡θB=1.5\tan\theta_B = 1.5

θB=tan⁡−1(1.5)\theta_B = \tan^{-1}(1.5)

Step 3: Evaluate

θB≈56.3∘\theta_B \approx 56.3^\circ …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.