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Exercise 12.1 · Q6

Q.Reduce the equation 5x−12y=605x - 12y = 60 to intercept form. Hence find the length of the portion of the line intercepted between the axes.

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Divide the given equation by its constant term to get intercept form, read off the intercepts, then use the distance formula between them.

Intercept form: xa+yb=1\dfrac{x}{a}+\dfrac{y}{b}=1 with xx-intercept aa, yy-intercept bb. Distance between (a,0)(a,0) and (0,b)(0,b): a2+b2\sqrt{a^2+b^2}.

  1. Given line. 5x−12y=605x - 12y = 60.

  2. Divide both sides by 6060 (the constant term) to bring it to the form xa+yb=1\dfrac{x}{a}+\dfrac{y}{b}=1:

5x60−12y60=1   ⟹   x12−y5=1\frac{5x}{60} - \frac{12y}{60} = 1 \ \implies\ \frac{x}{12} - \frac{y}{5} = 1

  1. Write the second term as a signed fraction to match the standard intercept form xa+yb=1\dfrac{x}{a}+\dfrac{y}{b}=1:

x12+y−5=1\frac{x}{12} + \frac{y}{-5} = 1

So the xx-intercept is a=12a=12 (line meets xx-axis at (12,0)(12,0)) and the yy-intercept is b=−5b=-5 (line meets yy-axis at (0,−5)(0,-5)).

  1. Find the length of the segment intercepted between the axes — the distance between (12,0)(12,0) and (0,−5)(0,-5): …

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