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Worked Examples · Example 6

Q.If M(a,b)(a, b) is the midpoint of a line segment intercepted between the axes, show that the equation of the line is xa+yb=2\frac{x}{a} + \frac{y}{b} = 2.

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Let the line meet the axes at (p,0)(p,0) and (0,q)(0,q); use the midpoint condition to express p,qp,q in terms of a,ba,b, then substitute into the standard intercept form.

Intercept form of a line with xx-intercept pp and yy-intercept qq:

xp+yq=1\frac{x}{p} + \frac{y}{q} = 1

Midpoint of (p,0)(p,0) and (0,q)(0,q): (p2,q2)\left(\dfrac{p}{2},\dfrac{q}{2}\right).

  1. Set up the intercepts. Suppose the line meets the xx-axis at (p,0)(p,0) and the yy-axis at (0,q)(0,q). Its equation in intercept form is

xp+yq=1(∗)\frac{x}{p} + \frac{y}{q} = 1 \qquad (\ast)

  1. Apply the midpoint condition. We are told the midpoint of the intercepted segment (joining (p,0)(p,0) and (0,q)(0,q)) is M(a,b)M(a,b):

(p+02,0+q2)=(a,b)   ⟹   p2=a, q2=b\left(\frac{p+0}{2}, \frac{0+q}{2}\right) = (a,b) \ \implies\ \frac{p}{2}=a, \ \frac{q}{2}=b

  1. Solve for pp and qq.

p=2a,q=2bp = 2a, \qquad q = 2b

  1. Substitute p=2ap=2a, q=2bq=2b into (∗)(\ast).

x2a+y2b=1\frac{x}{2a} + \frac{y}{2b} = 1

  1. Multiply both sides by 22 to clear the denominators' factor of 22: xa+yb=2\frac{x}{a} + \frac{y}{b} = 2 …

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