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Worked Examples · Example 5

Q.Consider the sets ϕ\phi; A={1,2,3}A = \{1, 2, 3\}; B={1,4,5}B = \{1, 4, 5\}; C={1,2,3,4,5}C = \{1, 2, 3, 4, 5\}; D={x:x∈N and x<4}D = \{x : x \in N \text{ and } x < 4\}. Insert the symbol '⊆\subseteq', '⊈\not\subseteq' or '==' between the following pairs of sets:

(i) ϕ\phi ___ BB
(ii) AA ___ BB
(iii) BB ___ CC
(iv) AA ___ DD
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✓ Free question

Compare element membership: X⊆YX\subseteq Y if every element of XX lies in YY; X=YX=Y if X⊆YX\subseteq Y and Y⊆XY\subseteq X; otherwise X⊈YX\not\subseteq Y.

Given ϕ={}\phi=\{\}, A={1,2,3}A=\{1,2,3\}, B={1,4,5}B=\{1,4,5\}, C={1,2,3,4,5}C=\{1,2,3,4,5\}, D={x∈N:x<4}D=\{x\in\mathbb{N}:x<4\}.

  1. First evaluate DD: natural numbers less than 44 are 1,2,31,2,3, so D={1,2,3}D=\{1,2,3\}.
  2. (i) ϕ\phi ___ BB. The empty set is a subset of every set (vacuously true). ϕ⊆B\phi \subseteq B.
  3. (ii) AA ___ BB. A={1,2,3}A=\{1,2,3\}, B={1,4,5}B=\{1,4,5\}. Is 2∈B2\in B? No. So not every element of AA is in BB: A⊈BA \not\subseteq B.
  4. (iii) BB ___ CC. B={1,4,5}B=\{1,4,5\}, C={1,2,3,4,5}C=\{1,2,3,4,5\}. Check: 1∈C1\in C ✓, 4∈C4\in C ✓, 5∈C5\in C ✓. All elements of BB are in CC: B⊆CB \subseteq C.
  5. (iv) AA ___ DD. A={1,2,3}A=\{1,2,3\}, D={1,2,3}D=\{1,2,3\}. Every element matches exactly, both ways: A=DA = D.
✓Final answer

(i) ϕ⊆B\phi\subseteq B (ii) A⊈BA\not\subseteq B (iii) B⊆CB\subseteq C (iv) A=DA=D.

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