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Worked Examples · Example 12

Q.Find 56(mod4)5^6 \pmod 4.

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Because 5≡1(mod4)5\equiv 1\pmod 4, every power of 55 is also ≡1\equiv 1, so 56 mod 4=15^6\bmod 4 = 1.

if a≡r(modm) then ak≡rk(modm)\text{if } a\equiv r\pmod m \text{ then } a^k\equiv r^k\pmod m

where aa is the base, kk the exponent and mm the modulus. Here a=5a=5, k=6k=6, m=4m=4.

  1. Reduce the base modulo 44: 5 mod 4=1(5=1×4+1)5\bmod 4 = 1\qquad(5 = 1\times 4 + 1) …

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