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Exercise 5.7 · Q2

Q.Find the second order derivative of the function: x20x^{20}

Puducherry CbseNCERTSubjective· 2mImportance★★★★★
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✓ Free question

Applying the power rule twice to x20x^{20} gives d2ydx2=380x18\dfrac{d^2y}{dx^2} = 380x^{18}.

A second-order derivative just means we differentiate, then differentiate the result again. For a pure power of xx the only tool we need is the power rule, ddxxn=n xn−1\frac{d}{dx}x^n = n\,x^{n-1} — no chain rule, no product rule.

Step 1 — First derivative

For y=x20y = x^{20},

dydx=20x20−1=20x19.\frac{dy}{dx} = 20x^{20-1} = 20x^{19}.

Step 2 — Second derivative

Now differentiate 20x1920x^{19}. The constant 2020 stays put; apply the power rule to x19x^{19}:

d2ydx2=20⋅19 x19−1=20⋅19 x18.\frac{d^2y}{dx^2} = 20\cdot 19\,x^{19-1} = 20\cdot 19\,x^{18}.

Step 3 — Simplify

Since 20×19=38020\times 19 = 380,

d2ydx2=380x18.\frac{d^2y}{dx^2} = 380x^{18}.

Tip

In one shot, d2dx2xn=n(n−1) xn−2\dfrac{d^2}{dx^2}x^n = n(n-1)\,x^{n-2}. With n=20n=20: 20⋅19=38020\cdot 19 = 380 and the exponent drops to 1818.

✓Final answer

d2ydx2=380x18\dfrac{d^2y}{dx^2} = 380x^{18}

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