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NCERT Exemplar · Q95

Q.If AA is skew symmetric matrix, then A2A^2 is a symmetric matrix.

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A skew-symmetric matrix satisfies AT=−AA^T = -A. Squaring it gives A2A^2, and taking its transpose shows (A2)T=A2(A^2)^T = A^2, proving A2A^2 is symmetric.

Why This Works: The Core Idea

A skew-symmetric matrix is one where flipping it across the main diagonal (transposing) gives back the negative of the original. In symbols: AT=−AA^T = -A. Think of it as a matrix that "anti-reflects" — every entry aija_{ij} is the negative of ajia_{ji}, and the diagonal entries are forced to be zero.

Now, when you square such a matrix, something interesting happens. The "negative sign" gets multiplied by itself, and two negatives make a positive. That's the heart of why A2A^2 ends up symmetric — the skew-symmetry gets "squared away."

Tip

This is a classic pattern: an odd power of a skew-symmetric matrix remains skew-symmetric (A3A^3 is skew-symmetric), but an even power becomes symmetric. The sign flips with each multiplication.

Step-by-Step Proof

1. Start with the definition of skew-symmetry.

We are given that AA is skew-symmetric. By definition:

AT=−AA^T = -A

This is the only fact we need — no special properties of AA beyond this.

2. Write what we want to prove.

We need to show A2A^2 is symmetric. A matrix MM is symmetric if MT=MM^T = M. So we need to check:

(A2)T=A2(A^2)^T = A^2

3. Use the transpose property for a product.

A fundamental rule: the transpose of a product is the product of the transposes in reverse order. That is:

(AB)T=BTAT(AB)^T = B^T A^T

Applying this to A2=A⋅AA^2 = A \cdot A:

(A2)T=(A⋅A)T=AT⋅AT(A^2)^T = (A \cdot A)^T = A^T \cdot A^T

4. Substitute the skew-symmetry condition.

Since AT=−AA^T = -A, we replace each ATA^T:

(A2)T=(−A)(−A)=(−1)(−1)⋅A⋅A=A2(A^2)^T = (-A)(-A) = (-1)(-1) \cdot A \cdot A = A^2 …

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