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NCERT Exemplar · Q87

Q.Transpose of a column matrix is a column matrix.

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The transpose of a column matrix is a row matrix, not a column matrix. The given statement is false.

Why This Matters: The Core Idea of Transpose

The transpose operation flips a matrix over its main diagonal — rows become columns, and columns become rows. This is a fundamental transformation in linear algebra, and getting it right is essential for matrix multiplication, solving systems, and understanding vector spaces.

A column matrix (also called a column vector) has only one column and any number of rows. For example:

A=[a1a2a3]A = \begin{bmatrix} a_1 \\ a_2 \\ a_3 \end{bmatrix}

has dimensions 3×13 \times 1 (3 rows, 1 column).

When you transpose it, every element that was in row ii, column 1 moves to row 1, column ii. So the result has 1 row and as many columns as the original had rows — that's a row matrix.

Step-by-Step Reasoning

  1. Recall the definition of transpose.

    If AA is an m×nm \times n matrix, its transpose ATA^T is an n×mn \times m matrix where (AT)ij=Aji(A^T)_{ij} = A_{ji}. In plain language: the first row of ATA^T is the first column of AA, the second row of ATA^T is the second column of AA, and so on.

  2. Apply this to a column matrix.

    Let CC be a column matrix of size m×1m \times 1:

C=[c1c2⋮cm]C = \begin{bmatrix} c_1 \\ c_2 \\ \vdots \\ c_m \end{bmatrix}

Here mm is the number of rows, and there is exactly 1 column.

  1. Perform the transpose. The first (and only) column of CC becomes the first row of CTC^T. So:

CT=[c1c2…cm]C^T = \begin{bmatrix} c_1 & c_2 & \dots & c_m \end{bmatrix}

This is a 1×m1 \times m matrix — exactly one row and mm columns.

  1. Check the dimensions. Original: m×1m \times 1 → Transpose: 1×m1 \times m. A 1×m1 \times m matrix is called a row matrix (or row vector), not a column matrix. …

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