If $f(x) = \begin{cases} x^{2}-4x & \text{if } x \geq 2 \\ x+2 & \text{if } x < 2 \end{cases}$ then, $f(0)$ is : (a) $-1$ (b) $2$ (c) $0$ (d) $5$

If f(x) = x²-4x if x ≥ 2 x+2 if x < 2 then, f(0) i – Class 11 Business Mathematics Statistics

Question 27 of 49

f(x) = \begin{cases} x^{2}-4x & \text{if } x \geq 2 \\ x+2 & \text{if } x < 2 \end{cases}

(a)

-1

(b)

2

(c)

0

(d)

5

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Because $0<2$ , use the branch $f(x)=x+2$ , giving $f(0)=2$ .

The function is defined piecewise:

$f(x) = \begin{cases} x^2 - 4x & \text{if } x \ge 2 \\ x + 2 & \text{if } x < 2 \end{cases}$

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