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Question 34 of 49

Q.If f(x)=x2−x+1f(x) = x^2 - x + 1, then f(x+1)f(x+1) is :

(a) 11
(b) x2x^2
(c) x2+x+1x^2 + x + 1
(d) xx
Puducherry TnboardTamil Nadu HSC First Year (DGE) Commerce Board 2023MCQ· 1mImportance★★★★★
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Substituting x+1x+1 into f(x)=x2−x+1f(x)=x^2-x+1 gives f(x+1)=x2+x+1f(x+1)=x^2+x+1, so the answer is option (c).

Given f(x)=x2−x+1f(x) = x^2 - x + 1, replace every xx with (x+1)(x+1):

f(x+1)=(x+1)2−(x+1)+1.f(x+1) = (x+1)^2 - (x+1) + 1.

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