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Question 37 of 49

Q.If y=e2xy=e^{2x}, then d2ydx2\dfrac{d^2y}{dx^2} at x=0x=0 is :

(a) 22
(b) 44
(c) 00
(d) 99
Puducherry TnboardTamil Nadu HSC First Year (DGE) Commerce Board 2024MCQ· 1mImportance★★★★★
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For y=e2xy=e^{2x}, the second derivative at x=0x=0 is 44.

Differentiate using the chain rule (the derivative of eue^{u} is eu⋅u′e^{u}\cdot u'):

dydx=e2x⋅2=2e2x.\frac{dy}{dx}=e^{2x}\cdot 2 = 2e^{2x}.

Differentiate again: …

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